1-3/y/1-9/y^2

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Solution for 1-3/y/1-9/y^2 equation: 


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

1-((3/y)/1)-(9/(y^2)) = 0

1-3*y^-1-9*y^-2 = 0

t_1 = y^-1

1-9*t_1^2-3*t_1^1 = 0

1-9*t_1^2-3*t_1 = 0

DELTA = (-3)^2-(-9*1*4)

DELTA = 45

DELTA > 0

t_1 = (45^(1/2)+3)/(-9*2) or t_1 = (3-45^(1/2))/(-9*2)

t_1 = (3*5^(1/2)+3)/(-18) or t_1 = (3-3*5^(1/2))/(-18)

t_1 = (3*5^(1/2)+3)/(-18)

y^-1-((3*5^(1/2)+3)/(-18)) = 0

1*y^-1 = (3*5^(1/2)+3)/(-18) // : 1

y^-1 = (3*5^(1/2)+3)/(-18)

-1 < 0

1/(y^1) = (3*5^(1/2)+3)/(-18) // * y^1

1 = ((3*5^(1/2)+3)/(-18))*y^1 // : (3*5^(1/2)+3)/(-18)

-18*(3*5^(1/2)+3)^-1 = y^1

y = -18*(3*5^(1/2)+3)^-1

t_1 = (3-3*5^(1/2))/(-18)

y^-1-((3-3*5^(1/2))/(-18)) = 0

1*y^-1 = (3-3*5^(1/2))/(-18) // : 1

y^-1 = (3-3*5^(1/2))/(-18)

-1 < 0

1/(y^1) = (3-3*5^(1/2))/(-18) // * y^1

1 = ((3-3*5^(1/2))/(-18))*y^1 // : (3-3*5^(1/2))/(-18)

-18*(3-3*5^(1/2))^-1 = y^1

y = -18*(3-3*5^(1/2))^-1

y in { -18*(3*5^(1/2)+3)^-1, -18*(3-3*5^(1/2))^-1 }

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